You are seeing this message because your Web browser does not support basic Web standards. Find out more about why this message is appearing and what you can do to make your experience on this site better.


ABOUT ARCHIVES
Advanced Search

Welcome   | My Account | E-mail Alerts | Access Rights | Sign In


  Vol. 119 No. 3, March 1984 TABLE OF CONTENTS
  Archives
  •  Online Features
  EDITORIAL
 This Article
 •Full text PDF
 •Send to a friend
 • Save in My Folder
 •Save to citation manager
 •Permissions
 Citing Articles
 •Contact me when this article is cited
 Related Content
 •Similar articles in this journal
 Social Bookmarking
  Add to CiteULike Add to Connotea Add to Del.icio.us Add to Digg Add to Reddit Add to Technorati Add to Twitter What's this?

Sequencing

BEN EISEMAN, MD

Arch Surg. 1984;119(3):263.

Since this article does not have an abstract, we have provided the first 150 words of the full text PDF and any section headings.

There are three valves on a trumpet. Even Louis Armstrong wove his magic using only the eight possible combinations of fingering. But if Satchmo blew three times, he could have 512 different combinations of valve depression.

The problem is similar in optimal sequencing, and also for surgeons trying to reach a diagnosis using the fewest laboratory tests in the least time and at the least cost. It has always been so, but suddenly has become relevant because of diagnosis-related groups and of the emerging number, complexity, and cost of diagnostic laboratory studies. The problem of sequencing, or precedent order, in its simplest form would involve only two tests (A and B), in which case there are three possible sequencing strategies. We could perform test A on the first day and test B on the second day. The sequence could be reversed, and finally both tests could be performed on the . . . [Full Text PDF of this Article]


Author Affiliations

Denver


Footnotes

If performed on one day, there is but one combination (A, B, C, D). If done on two days, there are 14 combinations. If spread over three days, there are 16 combinations, and if one test is done a day over the four days, there are 24 options. The sum of these (1+14+16+24) is 55.



Add to CiteULike CiteULike   Add to Connotea Connotea   Add to Del.icio.us Del.icio.us   Add to Digg Digg   Add to Reddit Reddit   Add to Technorati Technorati   Add to Twitter Twitter     What's this?





HOME | CURRENT ISSUE | PAST ISSUES | TOPIC COLLECTIONS | CME | SUBMIT | SUBSCRIBE | HELP
CONDITIONS OF USE | PRIVACY POLICY | CONTACT US | SITE MAP
 
© 1984 American Medical Association. All Rights Reserved.